Maths / Areas Of Parallelograms And Triangles / Area of Triangle

QUESTION
 

Diagonals AC and BD of parallelogram ABCD perpendicularly bisect each other at point P. Show that ar(large Delta ADP) = ar(large DeltaAPB).

EXPLANATION
Explain TypeExplanation Content
Text

AC and BD bisect each other at 90^0.

therefore   ABCD is a rhombus.

        DeltaADP cong Delta ABP

therefore  ar(DeltaADP) = ar(DeltaABP)           [By theorem]

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