Maths / Areas Of Parallelograms And Triangles / Area of Triangle

QUESTION
 

Find the area of the following quadrilateral.

EXPLANATION
Explain TypeExplanation Content
Text

AP = sqrt{10^2-8^2}=sqrt{36}=6 cm

QD = sqrt{10^2-8^2}=sqrt{36}=6 cm

Area of Trapezium ABCD =frac{h(a+b)}{2} =frac{8(6+18)}{2}=96 cm^2

We can also calculate by finding area of triangle APB, triangle BCQ, rectangle PQCB.

traingle APB = frac{1}{2} times 6times 8=24  cm^2

triangle BCQ = frac{1}{2} times 6times 8=24  cm^2

rectangle PQCB = 6times 8=48  cm^2

Total Area = 24 +24+48=96 cm^2

View Contents
(Concept based Learning and Testing for [6th - 10th], NTSE, Bank & Govt. Exams)
Self Learning
Testimonials
No Preview
PARENT FEEDBACK c/o Om Umang C/o ABHYAS Academy
 10th
Abhyas is a complete education Institute. Here extreme care is taken by teacher with the help of regular exam. Extra classes also conducted by the institute, if the student is weak.
Back
Courses We Offer
(Concept based Learning and Testing for [6th - 10th], NTSE, Bank & Govt. Exams)