Maths / Areas Of Parallelograms And Triangles / Parallelograms on Same Base and Between Same Parallels

QUESTION

 In the figure , ABCDis a teapezium. If DP $\dpi{80} \left | \right |$ BC, then which of the following relationship is true?

 OPTIONS A. AD=BC B. 2ar(PQB) = 1 ar(ABCD) C. ar(PBCD)=2 ar(PQD) D. $\dpi{80} \Delta$ ADP =$\inline \dpi{80} \Delta$PBQ
Right Option : C

EXPLANATION
Explain TypeExplanation Content
Text

ABCDis a teapezium. As DP $\dpi{80} \left | \right |$ BC, then PBCD is a parallelogram

Now the parallelogram PBCD and Triangle PQD are on the same base PD and between the same parallel as PD || BC.

ar(PBCD)=2 ar(PQD)

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