Maths / Areas Of Parallelograms And Triangles / Congruent Figures

QUESTION

 In the figure, $\dpi{80} <$DAB=$\dpi{80} <$ABC .if $\dpi{80} <$1=$\dpi{80} <$2, then choose a correct relationship from the following.

 OPTIONS A. $ar \Delta ADB \neq ar\Delta ACB$ B. $ar \Delta ADB = ar\Delta ACB$ C. ar $\dpi{80} \Delta$ ABD=2 ar$\dpi{80} \Delta$AOB D. 2 ar $\dpi{80} \Delta$ AOB=ar$\Delta$ACB
Right Option : B

EXPLANATION
Explain TypeExplanation Content
Text

$ar \Delta ADB = ar\Delta ACB$  because these triangles are congruent triangles.

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