Maths / Areas Of Parallelograms And Triangles / Relation between Area of Parallelogram and Triangle

QUESTION
 

In the figure,ABCD is a parallelogram and ABP is a triangle . If ar (APB)=16 sq. units,ar(ADP)+ar(BCP) will be

OPTIONS
A. 

8 sq. units

B. 

48 sq.units

C. 

32 sq. units

D. 

16 sq.units

Right Option : D

EXPLANATION
Explain TypeExplanation Content
Text

ABCD is a parallelogram and ABP is a triangle on the same base AB and between the same paralles the aea of ABCD = 2 times ABP

ar (APB)=16 sq.

Area of ABCD = 2 X 16 = 32 Sq units.

ar(ADP)+ar(BCP) = ar(ABCD) - ar(APB) = 32 - 16 = 16 sq units

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