Maths / Areas Of Parallelograms And Triangles / Relation between Area of Parallelogram and Triangle
In the figure,ABCD is a parallelogram and ABP is a triangle . If ar (APB)=16 sq. units,ar(ADP)+ar(BCP) will be
8 sq. units
32 sq. units
Right Option : D
| Explain Type||Explanation Content|
ABCD is a parallelogram and ABP is a triangle on the same base AB and between the same paralles the aea of ABCD = 2 times ABP
ar (APB)=16 sq.
Area of ABCD = 2 X 16 = 32 Sq units.
ar(ADP)+ar(BCP) = ar(ABCD) - ar(APB) = 32 - 16 = 16 sq units
(Concept based Learning and Testing for [6th - 10th], NTSE, Bank & Govt. Exams)