Maths / Areas Of Parallelograms And Triangles / Relation between Area of Parallelogram and Triangle

QUESTION

 In the given figure, p || q and BC || ADif ar $\dpi{120} \fn_jvn \large \dpi{110} \fn_phv \Delta ABE=16 \;cm^2$,Then ar(ABCD) is equal to ______________
 OPTIONS A. 16$\dpi{80} \fn_phv cm^2$ B. 48$\dpi{80} \fn_phv cm^2$ C. 32$\dpi{80} \fn_phv cm^2$ D. 8$\dpi{80} \fn_phv cm^2$
Right Option : C

EXPLANATION
Explain TypeExplanation Content
Text

as p and q are parallel lines and BC is parallel to AD

Therefore ABCD is a parallelogram

As ||gm ABCD and $\dpi{120} \fn_jvn \large \Delta$ ABEare on the same base and between same parallels

ar (ABCD) = 2 ar( ABE)=2 X 16 = 32 $\dpi{120} \fn_jvn \large cm^2$

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