Maths / Circles / Cyclic Quadrilateral

QUESTION

 ABCD is a quadrilateral. If $\angle EAB=135^o,$ what is the measure of $\angle C\;?$

 OPTIONS A. $135^o$ B. $45^o$ C. $90^o$ D. $67.2^o$
Right Option : A

EXPLANATION
Explain TypeExplanation Content
Text
 ABCD is a quadrilateral. If $\angle EAB=135^o,$$\large \angle BAD+ \angle EAB= 180^0$        Linear Pair$\large \angle BAD+ 135^0= 180^0$$\large \angle BAD= 180^0-135^0= 45^0$As ABCD is a cyclic quadrilateral$\large \angle BAD + \angle DCB = 180^0$$\large 45^0 + \angle DCB = 180^0$$\large \angle DCB = 180^0-45^0=135^0$

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