Maths / Circles / Cyclic Quadrilateral

QUESTION

 If $\angle x=60^o\;and \; \angle y=120^o,\;then\; \angle w-\angle z$ is equal to

 OPTIONS A. $\large 0^o$ B. $30^o$ C. $120^o$ D. $\large 60^o$
Right Option : D

EXPLANATION
Explain TypeExplanation Content
Text
 AECB is a cyclic quadrilateral$\large \angle ABC +\angle AEC = 180^0$$\large w^0+x^0= 180^0$$\large w^0= 180^0-x^0= 180^0-60^0= 120^0$FDHG is a cyclic quadrilateral$\large \angle FDH +\angle FGH = 180^0$$\large y^0+z^0= 180^0$$\large z^0= 180^0-y^0$$\large z^0= 180^0-120^0= 60^0$So$\large w^0-z^0= 120^0-60^0= 60^0$

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