Maths / Circles / Cyclic Quadrilateral

QUESTION

 In the figure, $\angle ABC=110^o\;and\;\angle DAB=80^o.$ Measure of $\angle ADC+\angle DCB$ is equal to

 OPTIONS A. $\large 150^o$ B. $190^o$ C. $180^o$ D. $\large 170^o^{}$
Right Option : D

EXPLANATION
Explain TypeExplanation Content
Text
 In the figure, $\angle ABC=110^o\;and\;\angle DAB=80^o.$AS ABCD is a cyclic quadrilateral$\large \angle ABC + \angle ADC= 180^0$$\large \angle ADC= 180^0- \angle ABC= 180^0-110^0= 70^0$$\large \angle DAB + \angle DCB= 180^0$$\large \angle DCB= 180^0-\angle DAB = 180^0-80^0=100^0$ $\angle ADC+\angle DCB=100^0+70^0=170^0$

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