Maths / Circles / Cyclic Quadrilateral

QUESTION

 In the given figure, points B, C, D and E are concyclic and $\angle CBE=130^o.$ Find $\angle FDC$

 OPTIONS A. $50^o$ B. $60^o$ C. $130^o$ D. $230^o$
Right Option : A

EXPLANATION
Explain TypeExplanation Content
Text
 In the given figure, points B, C, D and E are concyclicand $\angle CBE=130^o.$$\large \angle CBE+ \angle CDE= 180^0$$\large \angle CDE= 180^0-\angle CBE= 180^0 - 130^0=50^0$So $\angle FDC= 50^0$ Find $\angle FDC$
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