Maths / Circles / Angle at the Centre is Double The Angle at Circumference

QUESTION

 In the given figure if reflex  $\large \angle AOB = x,$ $\angle ACB$ is equal to ​​​​​​​

 OPTIONS A. $(180-x)^o$ B. $(360-x)^o$ C. $(180- \frac {x}{2})^o$ D. $(360-\frac {x}{2})^o$
Right Option : C

EXPLANATION
Explain TypeExplanation Content
Text
 In the given figure if reflex  $\large \angle AOB = x,$$\large \angle AOB = 360^0-x$$\angle ACB=\frac{\angle AOB}{2}= \frac{360^0-x}{2}= 180^0-\frac{x}{2}$ ​​​​​​​

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