Maths / Circles / Equal Chords of a Circle Subtend Equal Angle at the Centre

QUESTION

Prove that equal chords of a circle subtend equal angles at the centre of the circle.

EXPLANATION
Explain TypeExplanation Content
Text
 Given : AB = CDTo prove: $\fn_jvn \large \angle$1 = $\fn_jvn \large \angle$2proof : In $\fn_jvn \large \Delta$AOB and $\fn_jvn \large \Delta$ COD, AO = OC    (Radii of the circle) AB = CD  (Given)BO = OD  (Radii of the circle)$\fn_jvn \large \therefore \: \: \Delta AOB\cong \Delta COD\: by\: SSS\\\\ SO,\: \angle 1=\angle 2\: by\: CPCT.$Hence, eqyal chords subtend equal angles at the centre.

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