Maths / Constructions / Construction of a triangle given a base and base angle and the difference of other two sides
Construct a triangle PQR in which QR = 6cm, and PR - PQ = 2cm.
| Explain Type||Explanation Content|
As PR > PQ, the side containing the base angle Q is less than third side.
- Cut the line segment QS equal to PR-PQ=2 cm , from the ray QX extended on opposite side of base QR.
- Join SR and draw its perpendicular bisector ray AB which intersect SR at M.
- Let P be the intersection point of SX and perpendicular bisector AB. Then join PR.
- Thus ∆PQR is the required Triangle.
(Concept based Learning and Testing for [6th - 10th], NTSE, Bank & Govt. Exams)