Maths / Coordinate Geometry / Area of Triangle Using Coordinate

QUESTION

Find the area of triangle whose vertices are (a,a),(a+1,a+1),(a+2,a)

EXPLANATION
Explain TypeExplanation Content
Text

The area of the triangle formed by the vertices A(a,a), B(a+1,a+1) and C(a+2,a) is given by

$\dpi{120} \large \frac {1}{2}\left [ a(a+1-a)+(a+1)(a-a)+(a+2)(a-a-1) \right ]$

$\dpi{120} \large =\frac {1}{2}\left [ a(1)+(a+1)(0)+(a+2)(-1) \right ]$

$\dpi{120} \large =\frac {1}{2}\left [ a+0-a-2 \right ]$

$\dpi{120} \large =\frac {1}{2}\left [-2 \right ] = -1 sq\: units$

as area can not be negative, so we ignore the minus sign.

View Contents
(Concept based Learning and Testing for [6th - 10th], NTSE, Bank & Govt. Exams)
Self Learning
Testimonials
STUDENT FEEDBACK - Ayan ghosh C/o ABHYAS Academy
8th
My experience was very good with Abhyas academy. I am studying here from 6th class and I am satisfied by its results in my life. I improved a lot here ahead of school syllabus.

Other Testimonials

Courses We Offer
(Concept based Learning and Testing for [6th - 10th], NTSE, Bank & Govt. Exams)