Maths / Cube and Cube Roots / Perfect Cube

QUESTION

Examine the following are perfect cubes:

• 243
• 26136
• EXPLANATION
Explain TypeExplanation Content
Text

$(i)\: \: 243=(3\times3\times3)\times3\times3$

Here occurrence of 3 is not in multiple of '3', so 243 is not a perfect cube number.

$(ii)\: \: 21636=(2\times2\times2)\times(3\times3\times3)\times11\times11$

In 21636, prime number 11 does not occur in group of three, so 21636 is not a perfect cube number.

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