Maths / Cube and Cube Roots / Cube using Column Method

QUESTION

Find the cube of   $\dpi{120} \fn_jvn \large 24^3$ by using column method.

EXPLANATION
Explain TypeExplanation Content
Text

Here , a= 2 and b = 4.

By using column method, we have

 Column I      $\dpi{120} \fn_jvn \large a^3$ Column II     $\dpi{120} \fn_jvn \large 3\times a^2\times b$ Column III      $\dpi{120} \fn_jvn \large 3\times a\times b^2$ Column IV     $\dpi{120} \fn_jvn \large b^3$ $\dpi{120} \fn_jvn \large 2^3=8$         $\dpi{120} \fn_jvn \large +5$ $\dpi{120} \fn_jvn \large 3\times 2^2\times 4=48$                                $\dpi{120} \fn_jvn \large +10$ $\dpi{120} \fn_jvn \large 3\times 2\times 4^2=96$                                   $\dpi{120} \fn_jvn \large +6$ $\dpi{120} \fn_jvn \large 4^3=6\underline{4}$ $\dpi{120} \fn_jvn \large \underline{13}$ $\dpi{120} \fn_jvn \large 5\underline{8}$ $\dpi{120} \fn_jvn \large 10\underline{2}$

13                          8                                               2                                  4

$\dpi{120} \fn_jvn \large \therefore24^3=13824.$

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