Maths / Introduction to Trigonometry / Trigonometric ratios of Complementary Angles

QUESTION

$\dpi{120} \fn_jvn \large sin35^0.\; sin55^0 - cos 35^0.\; cos55^0$  =   ___________________

 OPTIONS A. 0 B. $\dpi{120} \fn_jvn \large \frac{1}{3}$ C. 2 D. $\dpi{120} \fn_jvn \large \frac{1}{4}$
Right Option : A

EXPLANATION
Explain TypeExplanation Content
Text

sin 35° sin 55° - cos 35° cos 55° = sin 35° sin (90° - 35°) - cos 35° cos (90° - 35°) = sin 35° cos 35° - cos 35° sin 35

[Since sin (90° -  θ) = cos θ and cos (90° -  θ) = sin θ]

= sin 35° cos 35° - sin 35° cos 35° =  0

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