Maths / Introduction to Trigonometry / Trigonometric Identities

QUESTION

Express the trigonometric ratio sec A in terms of cot A.

 OPTIONS A. $\dpi{120} \large \frac {1}{\sqrt {1+cot^2A}}$ B. $\dpi{120} \large \frac {\sqrt {1 -cot^2A}}{cotA}$ C. $\dpi{120} \large \frac {\sqrt {1+cot^2A}}{cotA}$ D. None of these
Right Option : C

EXPLANATION
Explain TypeExplanation Content
Text

We have,  $sec^2A=1+tan^2A=1+\frac {1}{cot^2A}=\frac {1+cot^2A}{cot^2A}$

$\Rightarrow \: \: \: \: \: \: \: secA=\frac {\sqrt {1+cot^2A}}{cotA}$

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