Maths / Introduction to Trigonometry / Trigonometric ratios for 60 degrees

QUESTION
 

The value for the expressionfrac{sqrt{13};cos ;60^0+2;sin; 60^0}{sqrt{13};cos; 60^0 -2;sin;60^0}  is ____________.

 

OPTIONS
A. 

sqrt{13}-2sqrt3sqrt{13}-2sqrt3

B. 

sqrt{13}+2sqrt3

C. 

(sqrt{13}-2sqrt3)^2

D. 

(sqrt{13}+2sqrt3)^2

Right Option : D

EXPLANATION
Explain TypeExplanation Content
Text

frac{sqrt{13};cos ;60^0+2;sin; 60^0}{sqrt{13};cos; 60^0 -2;sin;60^0}

frac{sqrt{13}frac{1}{2}+2frac{sqrt3}{2}}{sqrt{13}frac{1}{2}- 2frac{sqrt3}{2}}= frac{13+2sqrt3}{13-2sqrt3}

= frac{sqrt{13}+2sqrt3}{sqrt{13}-2sqrt3} X frac{sqrt{13}+2sqrt3}{sqrt{13}+2sqrt3}= frac{(sqrt{13}+2sqrt3)^2}{(sqrt{13})^2-(2sqrt3)^2}= (sqrt{13}+2sqrt3)^2

 

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