Maths / Introduction to Trigonometry / Trigonometric ratios for 30 degrees

QUESTION

The value for the following expression is ____________.

$\dpi{120} \fn_jvn \large \frac{6\;sin 30^0-2\sqrt3\;cos 30^0}{6\;sin 30^0 +2\sqrt3\;cos30^0}$

 OPTIONS A. -3 B. 3 C. 0 D. 6
Right Option : C

EXPLANATION
Explain TypeExplanation Content
Text

$\frac{6\;sin 30^0-2\sqrt3\;cos 30^0}{6\;sin 30^0 +2\sqrt3\;cos30^0}$

$\frac{6\;X\;\frac{1}{2}- 2\sqrt3 X\frac{\sqrt3}{2}}{6 \;X \;\frac{1}{2}+2\sqrt3 X\frac{\sqrt3}{2}}= \frac{3-3}{3+3}=0$

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