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It is observed that in square or rectangular gardens or parks. Some space in the form of path is left inside or outside or in between as cross paths.
Illustration: A footpath of uniform width 5 m runs round the inside of a rectangular park 38 m long and 32 m wide. Find the area of the path.
Solution: Let ABCD be the rectangular park and PQRS be the internal boundaries of the path.
We have, Length AB= 38 m and Breadth BC= 32 m:
Thus, Area of rectangle ABCD = AB BC = 38 m 32 m = 1216
Now, Length PQ = 38 m - 5 m - 5 m = 28 m and Breadth QR = 32 m - 5 m - 5 m = 22m
Area of rectangle PQRS = PQ RS = 28 m 22 m = 616
Area of footpath = Area of rectangle ABCD - Area of rectangle PQRS = 1216 - 616=600
Thus, Area of footpath =600
The area of the crossroads = Area of the two colored rectangles - Area of the red colored rectangle at the centre.
We are subtracting the area of the rectangle because we are taking it into consideration two times.
Illustration: A rectangular lawn is 30 m by 20 m .It has two roads each 2 m wide running in the middle of it, one parallel to the length and the other parallel to the breadth . Find the area of the roads.
Solution: Let EFGH and PQRS be the cross roads,
we have EH = 2 m and EF = 30 m, then
Area of path EFGH = EH EF = 2 m 30 m = 60
Now, for the other crossroad, PQ = 2 m and QR = 20 m,
then Area of path PQRS = PQ QR = 2 m 20 m = 40
Area KLMN is common to the both the paths: KL = 2 m and LM = 2 m, then Area of KLMN = KL LM = 2 m 2 m = 4
Total area covered as roads = Area of road EFGH + Area of road PQRS - Area of KLMN = 60 + 40 - 4 = 100 - 4 = 96
Thus, total area of the roads = 96