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5. This is a ONE TIME attempt test. Once started, it cannot be reversed or attempted again.
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1
Find the nature of the roots of
:Roots are real and equal
Roots are imaginary or complex.
Roots are real and unequal
None of these
2
Solve
5,4
5,-4
-5,-4
NONE
3
Find the value of discriminant for the equation
-1
97
4
What should be added to to make it a perfect square
5
7
8
11
One of the factor of the polynomial is 2x-1. The other factor is:
x-5
x+5
x+7
x+4
6
One of the factors of the expression is :
x+y
x-z
x-y
none of these
The product of two numbers is 640. Their difference is 12. Find these numbers.
12, 30
20, 32
30, 20
16, 40
In a bag, there are coins of 5, 2 and 1 Rs. in the ratio 2:3:5. If the bag contains Rs 10,500 in all, then how many 2 rupee coins are there?
1200
1500
1600
1000
9
The sum of ages of a son and his father is 35 years and the product of their ages is 150. Find their present ages
10 years and 25 years
5 years and 30 years
2 years, 33 years
12years, 23 years.
10
If the three numbers are in the ratio 2:3:5, so that the sum of their squares is 608. Find the numbers respectively.
8,12, 20
12, 8, 20
20, 8, 12
20,12,8
Express as a quadratic equation.
No, it is not a quadratic equation
12
Express product as sum of two terms
13
The sum of two numbers is 90 and the greater number exceeds thrice the smaller number by 14. The number is _______________
18, 72
19,71
20,70
15,75
14
55
-55
105
15
Express the following as a quadratic equation.
16
The factors of are ______________
Factorization is not possible
17
Express the following as the product of two factors:
3(5x-2)(5x-2)
3(5x+2)(5x+2)
3(5x+2)(5x-2)
3(5x+4)(5x+4)
18
A bag contains 50 p, 25 P and 10 p coins in the ratio 5: 9: 4, amounting to Rs. 206. Find the number of coins of each type.
50p coins=200,25p coins=360,10p coins=160
50p coins=200,25p coins=400,10p coins=120
50p coins=240,25p coins=360,10p coins=120
50p coins=205,25p coins=365,10p coins=150
19
The number of real roots of equation:=9 is:
20
The base of a right angled triangle is 2cm less than the perpendicular. The length of, the hypotenuse is 10 cm. Which of the following equations represents this situation?