Solving Statements Involving Age:
While solving Problems Involving Age, we consider the age to be found as x. If in the statement it is mentioned after certain years then that value is added in the age of all the people. Similarly if it is mentioned before or ago certain years then that value is subtracted from the age of all the people.
Example: Reena is four years older than Rohan. Five years ago, Rohan's age was four times Reena's age. Find the ages of Reena and Rohan.
Solution Let Rohan's age be x years. Then, Reena's age is (x+4)years.
Five years ago, Rohan's age was (x-5) years.
Reena's age was (x+4-5) years = (x-1) years.
It is given that five years ago Rohan's age was four times Reena's age.
Hence, Rohan's age = 6 years
Reena's age = (x+4) years = (6+4) years = 10 years.
Example 2: After 12 years I shall be 3 times as old as I was 4 years ago. Find my present age.
Solution Let my present age be x years. After 12 years my age will be (x+12) years.
4 years ago my age was (x - 4) years.
It is given that after 12 years I shall be 3 times as old as I was 4 years ago.
Thus, my present age is 12 years.
The ages of Rahul and Haroon are in the ratio 5 : 7. If four years later, the sum of their ages will be 56 years, then Rahul's present age is __________ | |||
Right Option : C | |||
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Anup is four times as old as his son. If the sum of their ages is 50, find their ages. | |||
Right Option : C | |||
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The age of a father is equal to the square of the age of his son. The sum of the age of the father and five times the age of the son is 66 years. Find their present ages. | |||
Right Option : A | |||
View Explanation |
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