Central Government Service
Program for SSC CGL
Self Learning
Free Topics
(Click here to know About SELF LEARNING)
MOCK TESTS
Few Available
(Click here to attempt Free Mock Test)
Concepts Learning Progress
Available
Course Progess
Self Learning Progress
Report Card
Revision / Exam Preparation
Theory Notes
Question Bank
Subjects Related Concepts
Test Generator
Free Topics
Reports
Available as Required.
VIDEOS
Few Available
Central Government Service
Program for SSC CGL
Self Learning
Available
(Click here to know About SELF LEARNING)
MOCK TESTS
8
(Click here to attempt Free Mock Test)
Concepts Learning Progress
Available
Test Generator
Syllabus / Topic Test
Solution and Detailed Analysis
Course Progess
Self Learning Progress
Report Card
Revision / Exam Preparation
Theory Notes
Test Generator
Subjects Related Concepts
Self Learning
Videos
Self Learning Exams
Practice
Self Learning - At Own Pace
Question Answers with Explaination
Reports
Question-wise Analysis
Strong, Moderate and weak Concepts
Remedial Tests for Weak Concepts
Achievements - Month/Subject & Subject / Month
Self Study Detail
Graphical View
Your Rankings - Month / Subject & Subject / Month
VIDEOS
678
SUBJECTS
Current Affair, Maths, English, History, Democratic Politics, Geography, Economics, Verbal Reasoning, Non Verbal Reasoning, General Awareness, Critical Reasoning, Verbal Ability, Vedic Maths, General Knowledge
First, all four sides of a rhombus are equal, meaning that if we find one side, we can simply multiply the side by four to find the perimeter.
Second, the diagonals of a rhombus are perpendicular bisectors of each other, thus giving us four right triangles and splitting each diagonal in half. Using Pythagorean Theorem on any one of them will give us the length of our sides.
Illustration: If the area of rhombus be 24 and one of its diagonals be 4 cm, find the perimeter of rhombus.
Solution :Let ABCD be a rhombus such that its one diagonals AC = 4 cm. Support the diagonals AC and BD intersect at O. We have, Area of rhombus ABCD = 24
Hence BD = 12cm. Thus, we have AC = 4 cm and BD = 12 cm
and
Since the diagonals of a rhombus bisect each other at right angle. Therefore, OAB is right triangle, right angled at O. Using Pythagoras theorem in
AOB, we have
=
+
=
+
= 4 + 36 = 40
Hence, Perimeter of the rhombus ABCD = cm =