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Banking And Insurance

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Maths / Surface Area and Volume / Volume of Cone
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Volume of Cone

Cone: A cone is a three-dimensional figure with one circular base. A curved surface connects the base and the vertex.

Volume of Cone: .The volume V of a cone with radius r is one-third the area of the base B times the height h.

Volume of the cone of radius r and height h = frac{1}{3}{pi}r^{2}h

Illustration: Find the volume of a right circular cone 1.02m high , if the radius of its base is 28 cm.

Solution: We know that the volume V of a right circular cone of radius r and height h is given V=frac{1}{3}{pi}r^{2}h.   Here,   r = 28cm   and h = 1.02 m = 1.02 X 100 cm = 102 cm

therefore V=frac{1}{3}times {frac{22}{7}}times 28times 28times 102=83776;cm^3

Illustration: A conical tent is 9 m high and the radius of its base is 12 m.

(i) What is the cost of the canvas required to make it, if a square metre canvas costs Rs 10?

(ii) How many persons can be accommodated in the tent, if each person requires 2 square metre on the ground and 15;m^{3} of space to breath in?

Solution: We have,

r = Radius of the base of the conical tent = 12 m

h = Height of the conical tent = 9 m

l = Slant height of the conical tent = sqrt{r^{2}+h^{2}}

                                                      =sqrt{(12)^{2}+9^{2}}

                                                      =sqrt{144+81}=sqrt{225};m

                                                       =15;m

(i) Area of the lateral surface = pi rl=frac{22}{7}times 12times 15;m^{2}

                                              =565.7;m^{2}

So, total cost of the canvas = Rs(565.2 X 10) = Rs 5652

(ii) Area of the base of the conical tent = pi r^{2}=frac{22}{7}times 12times 12;m^{2}

                                                             =452.16;m^{2}

As each person requires 2 sq. metres of floor area.

So, max number of persons who will have enough space on the ground =frac{452.16}{2}=226

Also, Volume of the conical tent =frac{1}{3}times Area;of;the;basetimes Height

Volume of the conical tent=frac{1}{3}times 452.16times 9;m^{3}

Volume of the conical tent = 1356.48 ;m^{3}

We have, air space required person =15;m^{3}

So, number of persons who will have enough air space to breath in =frac{1356.48}{15}=90

Between 226 and 90, the smaller number is 90.

Hence 90 persons can be accomodated.


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