Free Fall Under Gravity


 
 
Concept Explanation
 

Free Fall Under Gravity

Free Fall Under Gravity: Whenever objects fall towards the earth under the earth’s gravitational force alone, then these are called freely falling objects and such a motion is called free fall.

Acceleration due to Gravity (g): Whenever an object falls towards the earth, acceleration is involved. This acceleration is due to the earth’s gravitational pull and is called acceleration due to gravity (or acceleration due to the gravitational force of the earth). It is denoted by g. The SI unit of ‘g’ is the same as that of acceleration, i.e. . Let mass of the earth be ‘M’ and an object falling freely towards it be ‘m’. The distance between centres of the earth and the object is ‘R.’ From Newton’s law of gravitation,

F = frac{GMm}{R^2}

Also, from second law of motion, force exerted on object, F = ma. Since, a = g (i.e. acceleration due to gravity); F = mg. Equating RHS of Eqs. (i) and (ii), we get

mg = frac{GMm}{R^2};;or;;g = frac{GM}{R^2}

From the formula, it is clear that acceleration due to gravity does not depend on the mass of a falling object. It depends only on the mass of the earth or celestial bodies.  As distance of an object from the centre of the celestial body increases, the value of g decreases. Earth is flattened at poles. Thus, radius of the earth is less at poles than at equator. Hence, the value of g is less at equator than at poles.

Calculation of value of g: To calculate the value of g, we should put the values of G, M and R in the above formula 

Mass of Earth   M = 6 X 10^{24} kg.

Radius of Earth   R = 6.4 X 10^6 m.

Universal gravitational constant, G =6.67 X 10^{-11}N m^2/ kg^2

g = frac{GM}{R^2}= frac{6.67 X 10^{-11} X 6 X 10^{24}}{(6.4 X 10^6)^2}= 9.8 m/s^2

Motion of Objects under the Influence of Gravitational Force of the Earth: The three equations of motion we have derived earlier is for bodies under uniform acceleration. Since, in case of motion of bodies under free fall, there is also a uniform acceleration, i.e. acceleration due to gravity (g) acting downwards. So the previous three equations of motion can be applied for the motion of bodies under free fall as follows:

v= u+at;; Rightarrow ;; v= u+gt ;;; Equation; I

s= ut+frac{1}{2}at^2;; Rightarrow ;; h= ut+frac{1}{2}gt^2; ;;; Equation; II

v^2-u^2= 2as;; Rightarrow ;; v^2-u^2=2gh; ;;; Equation; III

Where, ‘h’ is the height from which the object falls, ‘t’ is the time fall, ‘u’ is the initial velocity and ‘v’ is the final velocity when body accelerates at g.

In solving numerical problems, we should remember the following points:

1. If an object falls vertically downwards, then acceleration due to gravity is taken as positive, since its velocity increases while falling.

2. If an object is thrown vertically upwards, then acceleration due to gravity is taken as negative, since its velocity decreases as it moves upward.

Q. A ball is thrown vertically upwards with a velocity of 25 m/s. If g is 10m/s^2, then calculate  (i)  height it reaches  (ii)  time taken to return back.

Solution: Given, initial velocity, u  =  25 m/s, fianl velocity,  v  =  0

                 If  a body is thrown upwards, then its velocity becomes zero at highest point, where it reaches, acceleration due to gravity,

                                                 g;=;-10m/s^2

(i)   therefore   Heiight, h:=;frac{v^2;-;u^2}{2g}:=:frac{0-(25)^2}{2(-10)}:=:frac{-625}{-20}:=;31.25: m

(ii) therefore Time, t = frac{v-u}{g}:=;frac{0-25}{-10}:=:2.5s

Time taken to return back, T = time of ascent + time of descent =  2t

Time taken to return back, T  =  2times2.5: =: 5;s

Sample Questions
(More Questions for each concept available in Login)
Question : 1

A ball is thrown vertically upwards. It has a speed of   large 10m/sec  ,when it has reached one half of its maximum height. How high does the ball rise? (Take g=10 ms^{-2})

Right Option : A
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Explanation
Question : 2

A ball is thrown vertically upwards with a velocity of    large x ;;m/sec    .  If the maximum height reached by the ball is 20 m , then the value of   x _____________

Right Option : C
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Explanation
Question : 3

Does a falling body accelerate ? Why?

Right Option : A
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Explanation
 
 


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