It is observed that in square or rectangular gardens or parks. Some space in the form of path is left inside or outside or in between as cross paths.
Illustration: A footpath of uniform width 5 m runs round the inside of a rectangular park 38 m long and 32 m wide. Find the area of the path.
Solution: Let ABCD be the rectangular park and PQRS be the internal boundaries of the path.
We have, Length AB= 38 m and Breadth BC= 32 m:
Thus, Area of rectangle ABCD = AB BC = 38 m 32 m = 1216
Now, Length PQ = 38 m - 5 m - 5 m = 28 m and Breadth QR = 32 m - 5 m - 5 m = 22m
Area of rectangle PQRS = PQ RS = 28 m 22 m = 616
Area of footpath = Area of rectangle ABCD - Area of rectangle PQRS = 1216 - 616=600
Thus, Area of footpath =600
The area of the crossroads = Area of the two colored rectangles - Area of the red colored rectangle at the centre.
We are subtracting the area of the rectangle because we are taking it into consideration two times.
A painting is painted on a cardboard 19 cm and 14 cm wide , such that there is a margin of 1.5 cm along each of its sides .Find the total area of the margin. | |||
Right Option : A | |||
View Explanation |
If the cost of paving a foot path on all the sides surrounding a park with sides 40 m and 36 m at the rate of Rs. 4 per sq. meter is Rs. 3440, what is the width of the foot path? | |||
Right Option : B | |||
View Explanation |
A plot is 100 m long and 60 m broad.A path 5 m wide runs breadth wise across the ground in the middle.Find the area of path. | |||
Right Option : B | |||
View Explanation |
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