While solving Problems Involving Age, we consider the age to be found as x. If in the statement it is mentioned after certain years then that value is added in the age of all the people. Similarly if it is mentioned before or ago certain years then that value is subtracted from the age of all the people.
Illustration: Reena is four years older than Rohan. Five years ago, Reena's age was five times Rohan's age. Find the ages of Reena and Rohan.
Solution Let Rohan's age be x years. Then, Reena's age is (x+4)years.
Six years ago, Rohan's age was (x-5) years.
Reena's age was (x+4-5) years = (x-1) years.
It is given that five years ago Reena's age was five times Rohan's age.
Hence, Rohan's age = 6 years
Reena's age = (x+4) years = (6+4) years = 10 years.
The sum of ages of a son and his father is 35 years and the product of their ages is 150. Find their present ages | |||
Right Option : B | |||
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The ages of Rahul and Haroon are in the ratio 5 : 7. If four years later, the sum of their ages will be 56 years, then Rahul's present age is __________ | |||
Right Option : C | |||
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5 years ago a man was 7 times as old as his son . He will be 3 times as old as his son after 5 years. Find their present ages. | |||
Right Option : C | |||
View Explanation |
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