Total surface area of a cuboid
Total Surface Area of a Cuboid
Total Surface Area of a Cuboid:
Total surface area of cuboid= , where,
l is the length of cuboid, b is the breadth of cuboid and h is the height of the cuboid.
Illustration: An indoor greenhouse is made entirely of glass panes held together with tape. It is 30cm long, 25cm wide, and 25cm height. Find the area of the glass?
Solution: We have, Length=30cm, Breadth=25cm and Height=25cm
Area of glass = Total surface area of cuboid =
= 2 (30 x 25 + 25 x 25 + 30 x 25)
= 2(750 + 625 + 750)
=
Illustration: A plastic box 1.5 m long, 1.25 m wide and 65 cm deep is to be made. It is to be open at the top. Ignoring the thickness of the plastic sheet, determine:
(i) The area of the sheet required for making the box.
(ii) The cost of the sheet for it, if a sheet measuring costs Rs 20.
Solution: We have,
l = Length of plastic box = 1.5 m
b = Breradth of plastic box = 1.25 m
h = height of plastic box = 65 cm = 65/100 = 0.65 m
Total surface area of the plastic box = lb + 2(bh + hl)
=
Hence the area of the sheet required for making the box is
(ii) Since sheet costs Rs 20. Therefore,
Cost of sheet required for making the box = Area of the sheet X Rate per sq. metre
= Rs (5.45 X 20)
= Rs 109
Find the surface area of the cuboid with length, breadth and height as 8cm, 5cm, and 4cm respectively. | |||
| Right Option : A | |||
| View Explanation | |||
If length, breadth, height and total surface area of a cuboid are l, b, h and s respectively, then which of the following relationships is true? | |||
| Right Option : A | |||
| View Explanation | |||
The length, breadth and height of a room are 5m, 4m and 3m respectively . Find the cost of white -washing the walls of the room and the ceiling at the rate of 7.50 per sq m. | |||
| Right Option : A | |||
| View Explanation | |||
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