Area of Path and Verandah


 
 
Concept Explanation
 

Area of Path and Verandah

Area of Path & Verandah: 

 It is observed that in square or rectangular gardens or parks. Some space in the form of path is left inside or outside or in between as cross paths.

Illustration: A footpath of uniform width 5 m runs round the inside of a rectangular park 38 m long and 32 m wide. Find the area of the path.

Solution: Let ABCD be the rectangular park and PQRS be the internal boundaries of the path.

We have, Length AB= 38 m and Breadth BC= 32 m:

Thus, Area of rectangle ABCD = AB large times BC = 38 m large times 32 m = 1216 large ^{m^{2}}

Now, Length PQ  = 38 m - 5 m - 5 m = 28 m and Breadth QR = 32 m - 5 m - 5 m = 22m

Area of rectangle PQRS = PQ large times RS = 28 m large times 22 m = 616 large ^{m^{2}}

Area of footpath = Area of rectangle ABCD - Area of rectangle PQRS = 1216 - 616=600 large ^{m^{2}}

Thus, Area of footpath =600 large ^{m^{2}}

The area of the crossroads = Area of the two colored rectangles - Area of the red colored rectangle at the centre.

We are subtracting the area of the rectangle because we are taking it into consideration two times.

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Sample Questions
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Question : 1

A painting is painted on a cardboard 19 cm and 14 cm wide , such that there is a margin of 1.5 cm along each of its sides .Find the total area of the margin.

Right Option : A
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Explanation
Question : 2

A plot is 100 m long and 60 m broad.A path 5 m wide runs breadth wise across the ground in the middle.Find the area of path.

Right Option : B
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Explanation
Question : 3

A garden is 90 m long and 75 m board. A path 5 m wide is to be built outside all around it along its border. Find the area of the path?

Right Option : B
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Explanation
 
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