Heron's Formula : In some cases, length of each side of the triangle are given but height of the triangle is neither given nor we are able to find in any way, then to find the area of such type of triangle, we use Heron's formula which is given below.
Area of triangle = , where a,b,c are length of the sides of a triangle and s is the semi-perimeter of the triangle i.e.
Example: Find the area of a quadrilateral ABCD in which AB = 3 cm, BC = 4 cm, CD = 4 cm, DA = 5 cm and AC = 5 cm. Solution : We divide the quadrilateral ABCD in two triangle ABC and ACD For ABC, a = 3, b = 4, c = 5 and Area (ABC) = = = 6 Similarly, for ACD, a = 5 cm, b = 5 cm, c = 4 cm and s = Area ( ACD ) = = = = Area of quadrilateral ABCD = Area of triangle ABC+ Area of triangle ACD = + |
The sides of a triangle are 16 cm, 30 cm and 34 cm Its area is: | |||
Right Option : C | |||
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The side of a triangle are 13 m, 14 m and 15 m, area of the triangle is: | |||
Right Option : C | |||
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The sides of a triangular field are 325 m 300 m and 125 m The area in sq. m. is ______________________. | |||
Right Option : A | |||
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