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While solving Problems Involving Age, we consider the age to be found as x. If in the statement it is mentioned after certain years then that value is added in the age of all the people. Similarly if it is mentioned before or ago certain years then that value is subtracted from the age of all the people.
Illustration: Reena is four years older than Rohan. Five years ago, Reena's age was five times Rohan's age. Find the ages of Reena and Rohan.
Solution Let Rohan's age be x years. Then, Reena's age is (x+4)years.
Six years ago, Rohan's age was (x-5) years.
Reena's age was (x+4-5) years = (x-1) years.
It is given that five years ago Reena's age was five times Rohan's age.
Hence, Rohan's age = 6 years
Reena's age = (x+4) years = (6+4) years = 10 years.
Illustration: After 12 years I shall be 3 times as old as I was 4 years ago. Find my present age.
Solution Let my present age be x years. After 12 years my age will be (x+12) years.
4 years ago my age was (x - 4) years.
It is given that after 12 years I shall be 3 times as old as I was 4 years ago.
Thus, my present age is 12 years.
Illustration: One year age Ramesh was 8 times as old as his son. Now his age is equal to the square of his son's age. Find their present age.
Solution: Let his son's age one year ago = x
Ramesh's age is one year ago= 8x
Present age of son = x+1
Present age of Ramesh = 8x + 1
According to the question:
either x = 0 or x = 6
As the age can not be zero so son's present age =x+1= 6+1=7 years
Ramesh's age= 8x+1 = 8(6)+1=48+1=49 years



