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Theorem: If a triangle and a parallelogram are on the same base and between the same parallels the area of the triangle is equal to half of the parallelogram.
Given A To prove Construction Draw Proof Since A, E and D are collinear and BC || AD
Now,
From Eq (1) and Eq (2) | ![]() |
ILLUSTRATION P and Q are any two points lying on the side DC and AD respectively of a parallelogram ABCD. Show that ar(APB)= ar(BQC)
Solution: Now
Similarly
From Eq (1) and Eq (2) Hence Proved | ![]() |