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Exterior Angle: If the side BC of a triangle ABC is produced to form ray BD, then is called an exterior angle of
at C and is denoted by ext.
Theorem: If a side of a triangle is produced, the exterior angle so formed is equal to the sum of the two interior opposite angles.
Given: A triangle ABC. D is a point on BC produced, forming an exterior angle To Prove: i.e., Proof: In triangle ABC, we have Also, Find (i) and (ii), we have Hence, i.e. |
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Illustration: in the figure PQ || RS. Find angle QOR.
Solution: Extend PQ to N [ Alternate interior angles are equal PN || RS and RO is the transversal ]
Now, In
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